Question about George Bayer birth rectification

1
Hi all,

I am learning Bayer's rectification method (Ebooks: Turning 400 years of Astrology to practical.pdf).

Step 1 and 2 is easy to understand as it is progression.However I don't understand where is "56 minutes" at Step 3 come from. Could anyone read this and explain for me?

Many many thanks,
Anh Tuan


"RECTIFICATION OF A CHART WHEN TIME OF
BIRTH IS UNKNOWN

We know that the Moon is the culprit that brings forth changes. We know the Moon?s daily progressed motion from birth on. Therefore, let us assume, we only know the day of birth and not the time or moment, whether morning, noon, or night. All we know is the place of birth and the day. The native usually remembers two or three events in his life that were of importance to him of which he recalls the exact day. Do not use marriages or children?s births for parents; they are caused by all sorts of aspects and by all sorts of combinations, by Venus, Mercury, MC, etc., aspects. Due to the fact that in most horoscopes Sun, Venus and Mercury are close together, you cannot distinguish which of the planets was the cause. We must take recourse to different events, such as: accidents, removal from place to place, sudden illnesses and their length, operations, a sudden windfall of money (inheritance, winnings, etc.).
These events depend as a rule on one of the following planets: Mars, Jupiter, Uranus
or Saturn.
? Mars brings sudden illness and fever;
? Jupiter brings money ( gains and losses);
? Uranus brings sudden changes of domicile or of employment;
? Saturn brings most anything that is slow and persistent (good or bad).

We erect the native?s horoscope with 0? Aries on the Ascendant. We enter the planets as of London Noon as shown in the Ephemeris of the day of birth. Supposing our native was born August 3rd, 1901, had an accident on May 25th, 1937. Supposing we do not know at what hour of August 3rd, 1901, he was born, i.e. the exact time. But we know he was born at the 14? East of Greenwich and at 48? North Latitude. The
accident happened May 25th, 1937. This is 35 years plus 295 days after birth.

Step No.1: The only horoscope we can make roughly (by using the planets? positions as of Noon London of the day of birth) are: the Radix and the Radix Mirrored Horoscopes. We make these two
horoscopes and place 0? Aries on the Ascendant, 0? Taurus on the cusp of the second house, etc., and enter the planets, as of August 3rd, 1901, together with their mirrored positions.

Step No.2: We enter in the ring (outside) the position of the Moon progressed as of 35 years 295 days later at Noon in London. This means: we take the Moon?s position 35 days after birth, i.e. for September 7th, 1901, and also figure out the proportionate movement this Moon has moved forward these 295 days, by dividing the motion from
Sept. 7th to Sept. 8th, 1901, by 365 and multiply the result of 295 (the days from August 3rd to May 25th, 1937). This value we add to the Noon position at London of Sept. 7th, 1901.

In the Ephemeris we find: Sept. 7th, Moon at 9? 1? Cancer Sept. 8th, Moon at 22? 32? Cancer.
Motion per day was 13? 31?. 13? 31? = 811?; 811?/365 = 2.22? per calendar day as motion of Moon between Sept.
7th and Sept. 8th, 1901, which, as we know, equals the period of August 3rd, 1936 to August 2nd, 1937.
When we multiply these 2.22? with 295 days after August 3rd, 1936, we obtain the additional motion of Moon since the birth day. Thus: 2.22 x 295 = 654.9? or 10? 55?.
This value we add to the Noon position at London of Sept. 7th, 1901. Therefore, 9? 1? Cancer plus 10? 55? equals 19? 56? Cancer as Moon position at Noon, progressed Moon for May 25th, 1937, the day of the accident.

Step No.3: The next step for us to take is to locate the Moon?s position for the exact Noon at the birth?s place. This we do with logarithms. Question: If the Moon at 12h 56m P.M. is at 19? 56? Cancer and its motion during the day is 13th 31?, how much does it move in 56 minutes? And where is this Moon 56 minutes prior?
log 13? 31? 2493
log 56? 1.4102
1.6595 or 32?

The Moon travelled in the 56 minutes just 32?. Therefore at Noon of that day it was at 19? 56? Cancer less 32? or at 19? 24? Cancer.

Step No.4: After knowing the Noon position of Moon at the place of birth, we also know the midnight position of both sides, i.e. for midnight Sept. 7th and for midnight Sept. 8th, 1901.
The day?s motion we know from the Ephemeris is 13? 31?, ? day
motion is 6? 45? or 6? 46?. This value we add and deduct from the Noon position 19? 24? Cancer. We get as midnight position on one side: 12? 39? Cancer and as midnight position on the other side: 26? 10? Cancer.

Step No.5: The limit wherein the Moon has to be at the time of the accident is therefore: 12? 39? Cancer to 26? 10? Cancer. It all depends when the native was born.
In order to find out when he was born we now look in the horoscopes and see whether or not we find that during the movement from 12? 39? Cancer to 26? 10? Cancer we meet with an aspect to an important planet that could have caused that event. Being an accident, it either was Mars or Saturn, possibly also the Ascendant (the one we look for). It could not have been a favorable aspect of any sort: thus, we do not look for trines or sextiles. We look for squares, oppositions, conjunctions or aspects of similar nature that bring about sudden changes for the worse.

Step No.6: Supposing we cannot find any aspect of that nature, we must not think that the native may have been born on some other day or that something is wrong. It may happen that we just struck a case where a Mundane Aspect or Mundane Mirrored
Aspect caused the event, of which we have no positions; else it might have been an Ascendant aspect. We simply begin all over again and take another event of importance. You will find that usually the first, second or at most the third test will give you the result, especially with accidents.
"

2
The Moon travelled in the 56 minutes just 32?. Therefore at Noon of that day it was at 19? 56? Cancer less 32? or at 19? 24? Cancer.
In 56 minutes of clock time the Moon moved 32 minutes of arc.

3
Hi Tom,

I know In 56 minutes of clock time the Moon moved 32 minutes of arc. But 32 minutes of arc is the result of 56.

What I want to know is: how to know it is 56m, not 55m or 57m?. Can we use 56m as constant for other case? If it is not constant, how to get it base on information in step 1 and step 2?

Best regards,

Anh Tuan

4
Tuanha,

Step No.3: The next step for us to take is to locate the Moon?s position for the exact Noon at the birth?s place. This we do with logarithms. Question: If the Moon at 12h 56m P.M. is at 19? 56? Cancer and its motion during the day is 13th 31?, how much does it move in 56 minutes? And where is this Moon 56 minutes prior?

You have to calculate the exact Position of the Moon at exact 12h 00m, but you know the position at 12h 56m. Position Moon at that time is 56 minutes to far.

5
Hi Ursa Major,

I see, so what you mean is we always suppose that we are at 12h56pm, and we can use this for other case (not just this tutorial).

Sorry for my bad English, I can understand so far as my explain above.

Many thanks for help!

6
Tuanha,

Your problem is those 56 minutes.

When it was at Noon (12h 00m) at London( 0 degrees East ), at birthplace the time was 56 minutes later ( 14 degrees East x 4 time minutes = 56 minutes).

So he made a correction for the longitude at birthplace ( 14 degrees East ) and
calculated for that birthplace at 12h 00m its position.